RA in the Cast of Friends? Which One?

While browsing international headlines, came upon comments about the US long-running tv show 'Friends'.  Learning of it's international success was one of the earliest surprises for me, after catching Armitage fever.  Happening today upon the following website, written by someone in India, finally made the extent of the Friends craze perfectly clear.
http://www.angelfire.com/me/SharadTheGenius/SharadsFriendsPage.html
Therefore, hoping most of you know of what I speak, as I ask which character RA might have played as a member of the cast of 'Friends'? There were 3 guys & 3 gals (see poll)...

                               L to R:  Ross, Rachel, Monica, Chandler, Phoebe, Joey

Ross - is Monica’s older brother. He has a Ph.D. - works as a paleontologist for a museum. His wife divorced him after informing him she’s a (pregnant w/his child) lesbian. Ross is somewhat shy, and had been madly in love with Rachel since the ninth grade. But Rachel didn't pay much attention to him. They finally get together - have a child, and plan to marry (in the final episode of the show).

Chandler - is an IT exec - earns a hefty salary. His dilemma, for a few seasons of the decade-long show, was that he had a very hard time both asking women out as well as breaking up with them once he did. During the final years of ‘Friends‘, he and Monica date, marry, adopt twins, then move to suburbia.

Joey - is an aspiring actor who engages in DIY projects(coincidence?:) and  continually gets rather pathetic roles(no coincidence). His hoped for breakthrough role was as Al Pacino's butt double in a movie, ‘but‘ that in the 'end' didn‘t work either. He finally won a role as an MD in a popular soap, but foolishly told a reporter during an interview that he often changed his lines. In the next scene, one of the writers gets his revenge by writing the role out of the show(the MD falls down an elevator shaft). It’s a good thing Joey is so cute because - to put it kindly - he could use a ton of enrichment from Enrich;)